Question

Is (0,−3)
a viable solution for the following system?

y<−5x+2


3y>3x−6


(1 point)

A) (0,−3) is a nonviable solution since it makes both inequalities true.

B) (0,−3) is a nonviable solution since it does not make both inequalities true.

C) (0,−3) is a viable solution since it makes both inequalities true.

D) (0,−3) is a viable solution since it makes one inequality true.

Answer 1

B) (0,−3) is a nonviable solution since it does not make both inequalities true.

Check: y < -5x + 2 → -3 < 2 (true).
3y > 3x − 6 → -9 > -6 (false). Thus it does not satisfy both.