Question

Is (0,−3)
a viable solution for the following system?

y<−5x+2


3y>3x−6


(1 point)

(0,−3)
is a nonviable solution since it makes both inequalities true.

(0,−3)
is a nonviable solution since it does not make both inequalities true.

(0,−3)
is a viable solution since it makes both inequalities true.

(0,−3)
is a viable solution since it makes one inequality true.

Answer 1

Test (0, −3):

1) y < −5x + 2 → −3 < 2, true.
2) 3y > 3x − 6 → −9 > −6, false.

Since it does not satisfy both inequalities, (0, −3) is a nonviable solution.