Asked by Christian
Greg is in a car at the top of a roller-coaster ride. The distance, d, of the car from the ground as the car descends is determined by the equation d = 144 – 16t2, where t is the number of seconds it takes the car to travel down to each point on the ride. For which interval of time is Greg’s car moving in the air?
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The car is in the air while d > 0. Solve
144 − 16t^2 > 0 ⇒ 16t^2 < 144 ⇒ t^2 < 9 ⇒ −3 < t < 3.
Since time t ≥ 0, the physical interval is 0 ≤ t < 3 seconds (it hits the ground at t = 3 s).
144 − 16t^2 > 0 ⇒ 16t^2 < 144 ⇒ t^2 < 9 ⇒ −3 < t < 3.
Since time t ≥ 0, the physical interval is 0 ≤ t < 3 seconds (it hits the ground at t = 3 s).
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