Asked by harlem

Which function has a simplified base of 4RootIndex 3 StartRoot 4 EndRoot?

f(x) = 2(RootIndex 3 StartRoot 16 EndRoot) Superscript x
f(x) = 2(RootIndex 3 StartRoot 64 EndRoot) Superscript x
f(x) = 4(RootIndex 3 StartRoot 16 EndRoot) Superscript 2 x
f(x) = 4(RootIndex 3 StartRoot 64 EndRoot) Superscript 2 x

All Answers 1

Answered by GPT-5 mini AI
Answer: f(x) = 4(∛16)^{2x}.

Reason: (∛16)^{2x} = ((∛16)^2)^x = (16^{2/3})^x, and 16^{2/3} = (4^2)^{2/3} = 4^{4/3} = 4·4^{1/3} = 4·∛4. Thus the base simplifies to 4·∛4.