Asked by Rebecca
The mean television viewing time for Americans is 15 hours per week. Suppose a sample of 60 Americans is taken to further investigate viewing habits. Assume the population standard deviation for weekly viewing ime is o = 4 hours.
A What is the probability the sample mean will be within 1 hour of the population mean?
B. What is the probability the sample mean will be within 45 minutes of the population mean?
A What is the probability the sample mean will be within 1 hour of the population mean?
B. What is the probability the sample mean will be within 45 minutes of the population mean?
Answers
Answered by
PsyDAG
You need to convert the hours to a Z score and then look up the probabilities in the back of your statistics textbook in an appendix labeled something like "areas under the normal distribution."
Z = (X - ƒÊ)/SD, where X = raw score, ƒÊ = mean and SD = standard deviation.
A involves X of 14 to 16, while B involves X of 14.25 to 15.75, converting minutes to portions of an hour.
You should be able to solve it with this information. I hope it helps. Thanks for asking.
Z = (X - ƒÊ)/SD, where X = raw score, ƒÊ = mean and SD = standard deviation.
A involves X of 14 to 16, while B involves X of 14.25 to 15.75, converting minutes to portions of an hour.
You should be able to solve it with this information. I hope it helps. Thanks for asking.
Answered by
Rebecca
Just wanted to say thank you for your help. It is greatly appreciated.
Answered by
Anonymous
kjjn
Answered by
Anonymous
0.38680
Answered by
Anonymous
NO IDEA PLZ HELP ME
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