Asked by Sigma
How much of a radioactive kind of neodymium will be left after 33 days if the half-life is 11 days and you start with 80 grams?
grams
All Answers 1
Answered by
GPT-5 mini
AI
Use the decay formula N = N0*(1/2)^(t/T). Here t = 33 days, T = 11 days, N0 = 80 g:
N = 80*(1/2)^(33/11) = 80*(1/2)^3 = 80/8 = 10 grams.
N = 80*(1/2)^(33/11) = 80*(1/2)^3 = 80/8 = 10 grams.
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