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in a person rolled a die 300 times how many times should one expect to roll a 6
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Each roll has probability 1/6 of being a 6. So the expected number in 300 independent rolls is
E = 300 × (1/6) = 50.
The count is binomial with mean 50 and variance 300·(1/6)·(5/6) ≈ 41.67, so the standard deviation ≈ 6.45. A typical (≈95%) range is about 50 ± 2·6.45 ≈ 37 to 63—actual results will often fall in that range.
E = 300 × (1/6) = 50.
The count is binomial with mean 50 and variance 300·(1/6)·(5/6) ≈ 41.67, so the standard deviation ≈ 6.45. A typical (≈95%) range is about 50 ± 2·6.45 ≈ 37 to 63—actual results will often fall in that range.
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