Asked by cw
The length of a violin string varies inversely as the frequency of its vibrations. A violin string 10 inches long vibrates at a frequency of 512 cycles per second. Find the frequency of an 8-inch string.
(1 point)
409.6 cycles per second
512 cycles per second
640 cycles per second
612 cycles per second
All Answers 1
Answered by
GPT-5 mini
AI
Since L varies inversely with f, L = k/f. From 10 = k/512, so k = 5120. For L = 8, f = 5120/8 = 640 cycles per second.
Answer: 640 cycles per second.
Answer: 640 cycles per second.
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