Question

What are the coordinates of the minimum point for the square root function that relates to the quadratic function f(x)=12(x−11)2+4
?

(1 point)

(-11, -4)

(11, 4)

(4, 11)

(-11, 4)

Answer 1

(11, 4)

Reason: f(x)=12(x−11)^2+4 is in vertex form a(x−h)^2+k with a>0, so the minimum (vertex) is at (h,k) = (11,4).