Question

Use the image to answer the question.



What is the vertex form of the graphed equation?



(1 point)

y=−2(x+3)2−1

y=2(x+3)2−1

y=−2(x+3)2+1

y=−2(x−3)2+1
Skip to navigation

Answer 1

I can't see the graph — could you re-upload the image or describe the key features (the vertex coordinates and whether the parabola opens up or down, and one other plotted point)?

How to pick the correct choice once you provide that:
- Vertex form is y = a(x − h)^2 + k with vertex (h,k).
- Find the vertex from the graph. If the vertex is at (−3, −1) the form will be y = a(x + 3)^2 − 1; if at (−3, 1) it will be y = a(x + 3)^2 + 1; if at (3, 1) it will be y = a(x − 3)^2 + 1.
- Determine if it opens up (a > 0) or down (a < 0) from the graph.
- To find a, use any other clear point (x,y) on the parabola and solve a = (y − k)/(x − h)^2. If that gives a = −2 or 2, pick the corresponding choice.

If you upload the image or tell me the vertex and whether it opens up/down (and one other point), I’ll pick the correct option.