Asked by bob
Use the image to answer the question.
A circle is plotted on a coordinate plane.
▶Click for Long Desc
What is the equation of the circle shown on the graph?
(1 point)
(x−4)2+(y+2)2=5
(x−2)2+(y−4)2=5
(x+2)2+(y+4)2=25
(x+4)2+(y−2)2=25
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All Answers 1
Answered by
GPT-5 mini
AI
I can’t see the image from here. Could you either paste the long description or tell me the center and one point on the circle (or the left/right/top/bottom intercepts)?
If you can read the graph yourself, here’s how to pick the right equation:
- Find the center (h,k) — it’s the circle’s centerpoint (midpoint of left/right and top/bottom extremes).
- Find the radius r as the distance from the center to any point on the circle (or to an extreme).
- The equation is (x−h)^2 + (y−k)^2 = r^2.
From the choices:
- (x−4)^2+(y+2)^2=5 has center (4,−2), r = √5.
- (x−2)^2+(y−4)^2=5 has center (2,4), r = √5.
- (x+2)^2+(y+4)^2=25 has center (−2,−4), r = 5.
- (x+4)^2+(y−2)^2=25 has center (−4,2), r = 5.
Tell me which center and radius you see and I’ll pick the correct option.
If you can read the graph yourself, here’s how to pick the right equation:
- Find the center (h,k) — it’s the circle’s centerpoint (midpoint of left/right and top/bottom extremes).
- Find the radius r as the distance from the center to any point on the circle (or to an extreme).
- The equation is (x−h)^2 + (y−k)^2 = r^2.
From the choices:
- (x−4)^2+(y+2)^2=5 has center (4,−2), r = √5.
- (x−2)^2+(y−4)^2=5 has center (2,4), r = √5.
- (x+2)^2+(y+4)^2=25 has center (−2,−4), r = 5.
- (x+4)^2+(y−2)^2=25 has center (−4,2), r = 5.
Tell me which center and radius you see and I’ll pick the correct option.
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