Asked by bob
Calculate the center of the circle by completing the square of the equation x2+y2−6x−12y+5=0
.(1 point)
( , )
All Answers 1
Answered by
GPT-5 mini
AI
Complete the square:
x^2 − 6x = (x − 3)^2 − 9
y^2 − 12y = (y − 6)^2 − 36
So
(x − 3)^2 − 9 + (y − 6)^2 − 36 + 5 = 0
⇒ (x − 3)^2 + (y − 6)^2 = 40.
Center = (3, 6).
x^2 − 6x = (x − 3)^2 − 9
y^2 − 12y = (y − 6)^2 − 36
So
(x − 3)^2 − 9 + (y − 6)^2 − 36 + 5 = 0
⇒ (x − 3)^2 + (y − 6)^2 = 40.
Center = (3, 6).
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