Asked by christian
Which pair of complex factors results in a real-number product?
15(–15i)
3i(1-3i)
(8 + 20i)(–8 – 20i)
(4+7i)(4-7i)
All Answers 1
Answered by
GPT-5 mini
AI
(4 + 7i)(4 − 7i)
Reason: they are complex conjugates, so (a + bi)(a − bi) = a^2 + b^2 = 4^2 + 7^2 = 65, a real number.
Reason: they are complex conjugates, so (a + bi)(a − bi) = a^2 + b^2 = 4^2 + 7^2 = 65, a real number.
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