Question

Which point should have an open circle in the graph of the piecewise function f(x)={−x−1 if x<1−x+2 if x≥1
?(1 point)

(1,−2)


(−1,1)


(1,1)


(−1,−2)

Answer 1

(1, −2)

Reason: The left piece −x−1 applies only for x<1, so its value at x=1 would be −1−1=−2 but x=1 is not included — an open circle at (1,−2). The right piece gives f(1)=−1+2=1 (filled).