Question

In a certain Algebra 2 class of 28 students, 21 of them play basketball and 20 of them play baseball. There are 5 students who play neither sport. What is the probability that a student chosen randomly from the class plays both basketball and baseball?

Answer 1

Number who play at least one sport = 28 − 5 = 23.

Let x = number who play both. Then 21 + 20 − x = 23, so x = 21 + 20 − 23 = 18.

Probability = 18/28 = 9/14 ≈ 0.6429.