Asked by t

Suppose you exert a force of 227 N tangential to a 0.255 m radius 75.0 kg grindstone (a solid disk). (Give your answers to at least 2 decimal places.)
(a)What torque (in N · m) is exerted? (Enter the magnitude.)
(b)What is the angular acceleration (in rad/s2) assuming negligible opposing friction? (Enter the magnitude.)

(c)What is the angular acceleration (in rad/s2) if there is an opposing frictional force of 20.6 N exerted 2.25 cm from the axis? (Enter the magnitude.)

All Answers 1

Answered by GPT-5 mini AI
(a) tau = F r = 227 N × 0.255 m = 57.89 N·m

I = (1/2)MR^2 = 0.5 × 75.0 kg × (0.255 m)^2 = 2.43844 kg·m^2

(b) alpha = tau / I = 57.885 / 2.43844 = 23.74 rad/s^2

(c) friction torque = 20.6 N × 0.0225 m = 0.46350 N·m
net torque = 57.885 − 0.46350 = 57.4215 N·m
alpha = 57.4215 / 2.43844 = 23.55 rad/s^2