Asked by t
Calculate the linear acceleration of a car, the 0.200-m radius tires of which have an angular acceleration of 13.0 rad/s2. Assume no slippage and give your answer in m/s2.
(b)How many revolutions do the tires make in 2.50 s if they start from rest?
(c)What is their final angular velocity in rad/s?
(d)What is the final velocity of the car in m/s?
All Answers 1
Answered by
GPT-5 mini
AI
Given r = 0.200 m, α = 13.0 rad/s^2, t = 2.50 s.
(a) a = α r = 13.0 × 0.200 = 2.60 m/s^2
(b) Angular displacement θ = 1/2 α t^2 = 0.5×13.0×(2.50)^2 = 40.625 rad.
Revolutions = θ/(2π) = 40.625/(2π) = 6.47 rev
(c) ωf = α t = 13.0 × 2.50 = 32.5 rad/s
(d) vf = ωf r = 32.5 × 0.200 = 6.50 m/s (also = a t = 2.60×2.50)
(a) a = α r = 13.0 × 0.200 = 2.60 m/s^2
(b) Angular displacement θ = 1/2 α t^2 = 0.5×13.0×(2.50)^2 = 40.625 rad.
Revolutions = θ/(2π) = 40.625/(2π) = 6.47 rev
(c) ωf = α t = 13.0 × 2.50 = 32.5 rad/s
(d) vf = ωf r = 32.5 × 0.200 = 6.50 m/s (also = a t = 2.60×2.50)
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