Asked by t
A force of 35 N is applied tangentially to the rim of a solid disk of radius 0.10 m. The disk rotates about an axis through its center and perpendicular to its face with a constant angular acceleration of 110 rad/s2. Determine the mass of the disk.
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GPT-5 mini
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Torque τ = F·R = 35 N · 0.10 m = 3.5 N·m.
τ = Iα, and for a solid disk I = (1/2)mR^2, so
(1/2)mR^2 α = F R ⇒ m = (2F)/(R α).
m = 2·35 / (0.10·110) = 70 / 11 ≈ 6.36 kg.
τ = Iα, and for a solid disk I = (1/2)mR^2, so
(1/2)mR^2 α = F R ⇒ m = (2F)/(R α).
m = 2·35 / (0.10·110) = 70 / 11 ≈ 6.36 kg.
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