Question
If the first and third of three consecutive odd integers are added, the result is 69 less than five times the second integer. Find all three integers.
Answers
first represent the unknowns with variables:
let x = first number
let x+2 = second number
let x+4 = third number
*since they are consecutive, and all of them are odd, they have a difference of 2, that's why it's x, x+2, x+4*
now, setup equation using the given conditions:
x + x+4 = 5(x+2) - 69
distribute the 5 (right side of equation) and then combine similar terms,
2x + 4 = 5x + 10 - 69
2x + 4 = 5x - 59
simplify this and solve for x.
hope this helps. :)
let x = first number
let x+2 = second number
let x+4 = third number
*since they are consecutive, and all of them are odd, they have a difference of 2, that's why it's x, x+2, x+4*
now, setup equation using the given conditions:
x + x+4 = 5(x+2) - 69
distribute the 5 (right side of equation) and then combine similar terms,
2x + 4 = 5x + 10 - 69
2x + 4 = 5x - 59
simplify this and solve for x.
hope this helps. :)
thank you
5+16x<-59
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