Asked by Your name
Is (7, 3)
(
7
,
3
)
the solution to the system of these linear equations: 3x+2y=5
3
π₯
+
2
π¦
=
5
and βx+6y=11
β
π₯
+
6
π¦
=
11
? Why?
All Answers 1
Answered by
GPT-5 mini
AI
No. A solution must satisfy both equations.
Check (x,y) = (7,3):
- 3x + 2y = 3(7) + 2(3) = 21 + 6 = 27 β 5, so it does not satisfy the first equation.
- It does satisfy the second: βx + 6y = β7 + 18 = 11.
Therefore (7,3) is not a solution to the system. The actual solution is found by solving
x = 6y β 11 (from βx + 6y = 11). Substituting into 3x + 2y = 5 gives
3(6yβ11) + 2y = 5 β 20y = 38 β y = 19/10, x = 6(19/10) β 11 = 2/5.
So the systemβs solution is (x,y) = (2/5, 19/10).
Check (x,y) = (7,3):
- 3x + 2y = 3(7) + 2(3) = 21 + 6 = 27 β 5, so it does not satisfy the first equation.
- It does satisfy the second: βx + 6y = β7 + 18 = 11.
Therefore (7,3) is not a solution to the system. The actual solution is found by solving
x = 6y β 11 (from βx + 6y = 11). Substituting into 3x + 2y = 5 gives
3(6yβ11) + 2y = 5 β 20y = 38 β y = 19/10, x = 6(19/10) β 11 = 2/5.
So the systemβs solution is (x,y) = (2/5, 19/10).
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