Question

Which equation has both 4 and
–
4 as possible values of x? Select all that apply.
x^2=2
x^2=16
x^2=64
x^3=2
x^3=16
x^3=64

Answer 1

x^2 = 16

Reason: 4^2 = 16 and (−4)^2 = 16. For the others either 4 and −4 do not satisfy the equation (e.g. x^2 = 2 or x^2 = 64) or the cube equations give different signs (e.g. x^3 = 64 is true for 4 but not for −4).