Question

Solve the system of two equations using elimination with multiplication.
4x−6y=−48

−2x+4y=30
(1 point)

(−21,−6)


(−3, 6)


(3, 9)


(−33,−9)

Answer 1

Multiply the second equation by 2: (-2x+4y=30)×2 → -4x+8y=60.
Add this to the first equation: (4x−6y=−48) + (-4x+8y=60) → 2y = 12 → y = 6.
Substitute y = 6 into 4x−6y=−48: 4x−36=−48 → 4x=−12 → x=−3.

Solution: (−3, 6).