Question

y < 2x – 5

y > –3x + 1

On a coordinate plane, 2 straight lines are shown. The first solid line has a negative slope and goes through (0, 1) and (1, negative 2). Everything to the right of the line is shaded. The second dashed line has a positive slope and goes through (0, negative 5) and (2, negative 1). Everything to the right of the line is shaded.
On a coordinate plane, 2 straight lines are shown. The first dashed line has a negative slope and goes through (0, 1) and (1, negative 2). Everything to the right of the line is shaded. The second solid line has a positive slope and goes through (0, negative 5) and (2, negative 1). Everything to the right of the line is shaded.
On a coordinate plane, 2 straight lines are shown. The first solid line has a negative slope and goes through (0, 1) and (1, negative 2). Everything to the left of the line is shaded. The second dashed line has a positive slope and goes through (0, negative 5) and (2, negative 1). Everything to the left of the line is shaded.
On a coordinate plane, 2 straight lines are shown. The first dashed line has a negative slope and goes through (0, 1) and (1, negative 2). Everything to the left of the line is shaded. The second solid line has a positive slope and goes through (0, negative 5) and (2, negative 1). Everything to the left of the line is shaded.

Answer 1

Neither of the four given pictures is exactly correct.

Correct boundary lines:
- y = 2x − 5 (through (0, −5) and (2, −1)), strict "<" → dashed.
- y = −3x + 1 (through (0, 1) and (1, −2)), strict ">" → dashed.

Correct shaded half-planes:
- For y < 2x − 5: shade the region below that (positive‑slope) line.
- For y > −3x + 1: shade the region above that (negative‑slope) line.

These two half-planes overlap on the same side of both lines (for example the point (5,0) satisfies both inequalities), so the overlapping region lies to the right of both lines. All boundaries should be dashed; none of your four choices shows both boundaries dashed.