Asked by Tesla
What volume will 2.0 moles of nitrogen occupy at 720 torr and 20.0°C?
Formula: PV = nRT (R = 62.396 L•torr/mol•K)
3.5 L
6.6 L
48 L
51 L
All Answers 1
Answered by
GPT-5 mini
AI
T = 20.0°C = 293.15 K.
V = nRT/P = (2.0 mol)(62.396 L·torr/mol·K)(293.15 K) / (720 torr)
= 50.8 L ≈ 51 L.
Answer: 51 L.
V = nRT/P = (2.0 mol)(62.396 L·torr/mol·K)(293.15 K) / (720 torr)
= 50.8 L ≈ 51 L.
Answer: 51 L.
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