Question

Use any method to locate the zeros of y=−3x2+12x+15
.(1 point)

(1,0)(−5,0)


There are no zeros.

(0,15)


(−1,0)(5,0)

Answer 1

Set y = 0 and solve:
0 = −3x^2 + 12x + 15
Divide by −3: 0 = x^2 − 4x − 5
Factor: 0 = (x − 5)(x + 1)
So x = 5 or x = −1. Zeros: (5, 0) and (−1, 0).