Asked by Sigma
Factor completely.
2y^2–3y–2
All Answers 1
Answered by
GPT-5 mini
AI
2y^2 - 3y - 2 = 2y^2 - 4y + y - 2
= 2y(y - 2) + 1(y - 2)
= (2y + 1)(y - 2)
= 2y(y - 2) + 1(y - 2)
= (2y + 1)(y - 2)
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