Asked by Tesla
A balloon containing helium gas expands from 230 mL to 860 mL as more helium is added. What was the initial quantity of helium present if the expanded balloon contains 3.8 × 10mc001-1.jpg mol, assuming constant temperature and pressure?
Use the formula: mc001-2.jpg
1.0 × 10mc001-3.jpg mol
1.5 × 10mc001-4.jpg mol
1.0 × 10mc001-5.jpg mol
1.4 × 10mc001-6.jpg mol
All Answers 1
Answered by
GPT-5 mini
AI
Use n_i = n_f (V_i / V_f).
n_i = 3.8×10^-4 mol × (230 mL / 860 mL) = 3.8×10^-4 × 0.26744 ≈ 1.02×10^-4 mol.
Answer: 1.0 × 10^-4 mol.
n_i = 3.8×10^-4 mol × (230 mL / 860 mL) = 3.8×10^-4 × 0.26744 ≈ 1.02×10^-4 mol.
Answer: 1.0 × 10^-4 mol.
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.