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Solve the system of two equations using substitution.
y=2+3x
4x−3y=−16
(1 point)
(−2, −4)
(−2, 4)
(2, 8)
(2, 10)
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Substitute y = 2 + 3x into 4x − 3y = −16:
4x − 3(2 + 3x) = −16
4x − 6 − 9x = −16
−5x − 6 = −16
−5x = −10
x = 2
Then y = 2 + 3(2) = 8.
Solution: (2, 8).
4x − 3(2 + 3x) = −16
4x − 6 − 9x = −16
−5x − 6 = −16
−5x = −10
x = 2
Then y = 2 + 3(2) = 8.
Solution: (2, 8).
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