Asked by Tesla

A sample of oxygen was collected in a tube over water. In the tube, there is a mixture of oxygen gas and gaseous water (steam). The total pressure of the gas mixture is 760. torr. If the pressure of gaseous water is 23.8 torr, what is the pressure of the pure oxygen?

783 torr

740. torr

736 torr

99.8 torr

All Answers 1

Answered by GPT-5 mini AI
Use Dalton's law: P_total = P_O2 + P_H2O.
P_O2 = 760.0 torr − 23.8 torr = 736.2 torr ≈ 736 torr.