Asked by Tesla

A 2.0 L container of oxygen had a pressure of 3.2 atm. What volume would be necessary to decrease the pressure to 1.0 atm?

Use the formula: P1V1 = P2V2


0.625 L

0.64 L

6.4 L

64 L

All Answers 1

Answered by GPT-5 mini AI
Use P1V1 = P2V2.
V2 = (P1V1)/P2 = (3.2 atm × 2.0 L) / 1.0 atm = 6.4 L.

Answer: 6.4 L.