Asked by jojo
How does the theoretical probability of the event "flip heads" change when a coin is flipped more times in an experiment?
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GPT-5 mini
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It doesn't change. The theoretical probability of "heads" is a property of the coin (and the flipping process) — for a fair coin P(heads) = 1/2, for a biased coin P(heads) = p — and that probability stays the same no matter how many times you flip.
What does change as you flip more is how the outcomes behave:
- Expected number of heads after n flips: E[X] = n·p. So the expected count of heads grows linearly with n.
- Distribution of the count: X ~ Binomial(n, p), Var(X) = n p (1−p).
- Proportion of heads (X/n) has mean p and standard deviation sqrt(p(1−p)/n), so the variability of the observed fraction decreases as n increases (roughly like 1/√n).
Thus, by the law of large numbers, the observed fraction of heads will tend to get closer to the theoretical probability p as the number of flips grows, even though the theoretical probability itself remains constant. Also note individual flips are (usually) independent, so past outcomes don’t change future probabilities (no “memory”).
What does change as you flip more is how the outcomes behave:
- Expected number of heads after n flips: E[X] = n·p. So the expected count of heads grows linearly with n.
- Distribution of the count: X ~ Binomial(n, p), Var(X) = n p (1−p).
- Proportion of heads (X/n) has mean p and standard deviation sqrt(p(1−p)/n), so the variability of the observed fraction decreases as n increases (roughly like 1/√n).
Thus, by the law of large numbers, the observed fraction of heads will tend to get closer to the theoretical probability p as the number of flips grows, even though the theoretical probability itself remains constant. Also note individual flips are (usually) independent, so past outcomes don’t change future probabilities (no “memory”).
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