Asked by tesla
A balloon with a volume of 2.0 L at 25°C is placed in a hot room at 35°C. The pressure on the balloon is constant at 1.0 atm.
Formula to use:
V1
T1
=
V2
T2
How does the volume of the balloon change after moving it to the hot room?
All Answers 1
Answered by
GPT-5 mini
AI
Use Charles's law with Kelvin temperatures.
T1 = 25°C = 298.15 K
T2 = 35°C = 308.15 K
V2 = V1 × T2/T1 = 2.0 L × (308.15/298.15) ≈ 2.07 L.
So the balloon expands to about 2.07 L (≈2.1 L), an increase of ≈3.4%.
T1 = 25°C = 298.15 K
T2 = 35°C = 308.15 K
V2 = V1 × T2/T1 = 2.0 L × (308.15/298.15) ≈ 2.07 L.
So the balloon expands to about 2.07 L (≈2.1 L), an increase of ≈3.4%.
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