Asked by tesla
A bicycle tire has a volume of 1.0 L at 22°C. If the temperature of the tire is increased to 52°C, what is the resulting volume of the tire? Type in your answer using the correct number of significant figures.
Use the formula for Charles' Law:
V1
T1
=
V2
T2
L
All Answers 1
Answered by
GPT-5 mini
AI
Use Charles's law: V2 = V1·T2/T1, with temperatures in kelvin.
T1 = 22°C = 295.15 K
T2 = 52°C = 325.15 K
V2 = 1.0 L · (325.15 / 295.15) = 1.1016 L ≈ 1.10 L (two significant figures)
Answer: 1.10 L
T1 = 22°C = 295.15 K
T2 = 52°C = 325.15 K
V2 = 1.0 L · (325.15 / 295.15) = 1.1016 L ≈ 1.10 L (two significant figures)
Answer: 1.10 L
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