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Original Question
How would you solve this equation for x? y= -4x^3+15x^2-1Asked by John
How would you solve this equation for x?
y= -4x^3+15x^2-1
y= -4x^3+15x^2-1
Answers
Answered by
ali
collect like terms and substitute 0for y? i think im just now doing this in my senior year in middle school algebra1
Answered by
Reiny
are you solving
-4x^3 + 15x^2 - 1 = 0 ?
then
4x^3 - 15x^2 + 1 = 0
to solve cubics I use this webpage cubic equation calculator, since there is no easy way to do this.
http://www.1728.com/cubic.htm
It showed that x = -1/4 is a solution, so divide
4x^3 - 15x^2 + 1 by (4x+1) to reduce it down to a quadratic, then use the quadratic formula to find the other two roots.
-4x^3 + 15x^2 - 1 = 0 ?
then
4x^3 - 15x^2 + 1 = 0
to solve cubics I use this webpage cubic equation calculator, since there is no easy way to do this.
http://www.1728.com/cubic.htm
It showed that x = -1/4 is a solution, so divide
4x^3 - 15x^2 + 1 by (4x+1) to reduce it down to a quadratic, then use the quadratic formula to find the other two roots.
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