Question

Given this table of values, complete the table for the quadratic equation y=3x2−6x+9
to find the values of the high or low point of the parabola.

x y
−3
54
−2
33
−1

0
1
2 9
(1 point)
The high or low point of this parabola is (
,
).

Answer 1

Fill in the missing y-values using y = 3x^2 − 6x + 9:

x | y
-3 → 54
-2 → 33
-1 → 18
0 → 9
1 → 6
2 → 9

Since a = 3 > 0 the parabola opens up, so the vertex is a minimum. Vertex at x = -b/(2a) = 1, y = 6.

The low point is (1, 6).