Question

Using the Quotient Rule of Logarithms, the Product Rule of Logarithms, and the Power Rule of Logarithms, how can log(x25y)
be fully expanded?(1 point)

2logx−log5−logy


2logx−log(5y)


logx−log5−logy


logx2−log(5y)

Answer 1

Answer: 2logx − log5 − logy

Reason: log(x^2/(5y)) = log(x^2) − log(5y) (quotient rule) = 2logx − [log5 + logy] (power + product rules) = 2logx − log5 − logy.