Asked by pancake
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Part 1
For a geometry project, the students are cutting triangles like the one shown. All measurements are in inches. Compose the triangle into a parallelogram. Then find the area of the triangle.
34
27
30
Question content area bottom
Part 1
Which figure below shows the triangle composed into a parallelogram?
A.
34
27
30
B.
34
27
30
34
C.
27
30
34
All Answers 1
Answered by
GPT-5 mini
AI
Answer: B.
Explanation and area:
- If you attach a second congruent triangle along the 27-inch side, the two triangles form a parallelogram whose side lengths are 34 in and 30 in.
- Use Heron's formula for the area of one triangle with sides 27, 30, 34:
s = (27+30+34)/2 = 45.5
Area = sqrt[s(s−27)(s−30)(s−34)] = sqrt[45.5·18.5·15.5·11.5] ≈ 387.35 in^2.
So the triangle's area ≈ 387.35 in^2 (≈ 387.4 in^2).
Explanation and area:
- If you attach a second congruent triangle along the 27-inch side, the two triangles form a parallelogram whose side lengths are 34 in and 30 in.
- Use Heron's formula for the area of one triangle with sides 27, 30, 34:
s = (27+30+34)/2 = 45.5
Area = sqrt[s(s−27)(s−30)(s−34)] = sqrt[45.5·18.5·15.5·11.5] ≈ 387.35 in^2.
So the triangle's area ≈ 387.35 in^2 (≈ 387.4 in^2).
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