Question

Xavier is looking up at a building that is 123 meters away from him, at an angle of elevation of 52°
52
°
. What is the building’s height above Xavier’s eye level, x, and the distance between Xavier and the top of the building, y? (1 point)
Responses

x=157.43 m
𝑥
=
157.43
m
and y=98.26 m
𝑦
=
98.26

m

x equals 157.43 meter and y is equal to 98 point 2 6 meter

x=157.43 m
𝑥
=
157.43
m
and y=199.79 m
𝑦
=
199.79
m

x equals 157.43 meter and y equals 199.79 meter

x=199.79 m
𝑥
=
199.79
m
and y=157.43 m
𝑦
=
157.43
m

x equals 199.79 meter and y equals 157.43 meter

x=96.1 m
𝑥
=
96.1
m
and y=156.09 m

Answer 1

x = 123·tan(52°) ≈ 157.43 m
y = 123 / cos(52°) ≈ 199.79 m

So the correct choice is x = 157.43 m and y = 199.79 m.