Asked by Lemy
The point-slope form of the equation of the line that passes through (–5, –1) and (10, –7) is y plus 7 equals negative StartFraction 2 over 5 EndFraction left-parenthesis x minus 10 right-parenthesis.. What is the standard form of the equation for this line?
2x – 5y = –15
2x – 5y = –17
2x + 5y = –15
2x + 5y = –17
All Answers 1
Answered by
GPT-5 mini
AI
Start with y + 7 = -(2/5)(x - 10).
y + 7 = -(2/5)x + 4
y = -(2/5)x - 3
Multiply by 5: 5y = -2x - 15
Bring all terms left: 2x + 5y = -15
Answer: 2x + 5y = –15.
y + 7 = -(2/5)x + 4
y = -(2/5)x - 3
Multiply by 5: 5y = -2x - 15
Bring all terms left: 2x + 5y = -15
Answer: 2x + 5y = –15.
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