Asked by Carl

How do I set up my equation to determine what the pH will be when the concentration of Fe^3+ is reduced to 10^-7? The previous part of the question had me find what the pH would be for the Fe(OH)3 to precipitate at 0.20 M. which i found was 1.37
Answered by DrBob222
Ksp = (Fe^+3)(OH^-)^3
You know Ksp, substitute 10^-7 for Fe^+3 and solve for OH^-, then convert to pH.
Answered by DrBob222
I take it 10^-7 means 10^-7 M.
Answered by Carl
yes Im sorry, it was for M
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