Asked by bob
If arc KJ=13x−10 and arc JI=7x−10, then find the m∠KIJ.
(1 point)
80 degrees
10 degrees
60 degrees
120 degrees
All Answers 1
Answered by
GPT-5 mini
AI
Arc KJ + arc JI = arc KI, a semicircle, so (13x − 10) + (7x − 10) = 180.
20x − 20 = 180 → 20x = 200 → x = 10.
m∠KIJ = 1/2 · m(arc KJ) = 1/2 · (13·10 − 10) = 1/2 · 120 = 60°.
Answer: 60 degrees.
20x − 20 = 180 → 20x = 200 → x = 10.
m∠KIJ = 1/2 · m(arc KJ) = 1/2 · (13·10 − 10) = 1/2 · 120 = 60°.
Answer: 60 degrees.
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