Asked by Name
Point S
š
is on the circle.
Which correctly shows that point S
š
lies on the circle?
(1 point)
Responses
(3+3)2+(ā7+4)2=45
(
3
+
3
)
2
+
(
ā
7
+
4
)
2
=
45
(6)2+(ā3)2=45
(
6
)
2
+
(
ā
3
)
2
=
45
36+9=45
36
+
9
=
45
Table with 1 columns and 3 rows.Row 1: Column 1, 'open paren 3 plus 3 close paren squared plus open paren negative 7 plus 4 close paren squared is equal to 45' Row 2: Column 1, '6 squared plus negative 3 squared is equal to 45' Row 3: Column 1, '36 plus 9 is equal to 45'
(3ā3)2+(ā7+4)2=9
(
3
ā
3
)
2
+
(
ā
7
+
4
)
2
=
9
(0)2+(ā3)2=9
(
0
)
2
+
(
ā
3
)
2
=
9
0+9=9
0
+
9
=
9
Table with 1 columns and 3 rows.Row 1: Column 1, 'open paren 3 minus 3 close paren squared plus open paren negative 7 plus 4 close paren squared is equal to 9' Row 2: Column 1, '0 squared plus negative 3 squared is equal to 9' Row 3: Column 1, '0 plus 9 is equal to 9'
(3ā3)2+(ā4ā7)2=121
(
3
All Answers 1
Answered by
GPT-5 mini
AI
Use the circle equation (x ā h)^2 + (y ā k)^2 = r^2 with center (ā3, ā4) and r^2 = 45. For S(3, ā7):
(3 ā (ā3))^2 + (ā7 ā (ā4))^2 = (3+3)^2 + (ā7+4)^2 = 6^2 + (ā3)^2 = 36 + 9 = 45.
So the first option ā (3+3)^2 + (ā7+4)^2 = 45 (6^2 + (ā3)^2 = 45; 36 + 9 = 45) ā correctly shows S lies on the circle.
(3 ā (ā3))^2 + (ā7 ā (ā4))^2 = (3+3)^2 + (ā7+4)^2 = 6^2 + (ā3)^2 = 36 + 9 = 45.
So the first option ā (3+3)^2 + (ā7+4)^2 = 45 (6^2 + (ā3)^2 = 45; 36 + 9 = 45) ā correctly shows S lies on the circle.
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