Asked by Makayla
A large concrete water pipe is being laid underground. The pipe has a diameter of 24 inches and is laid in 40 foot sections. How many cubic feet of water does each section hold? (Use 3.14 for the value of pi). Show all calculations.
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We use the volume formula for a cylinder: V = π r^2 h.
1. Diameter = 24 in → radius r = 24/2 = 12 in. Convert to feet: 12 in = 1 ft, so r = 1 ft.
2. Length (height) h = 40 ft.
3. Substitute (use π = 3.14):
V = π r^2 h = 3.14 × (1 ft)^2 × 40 ft
= 3.14 × 1 × 40 ft^3
= 125.6 ft^3.
Each 40-foot section holds 125.6 cubic feet of water.
1. Diameter = 24 in → radius r = 24/2 = 12 in. Convert to feet: 12 in = 1 ft, so r = 1 ft.
2. Length (height) h = 40 ft.
3. Substitute (use π = 3.14):
V = π r^2 h = 3.14 × (1 ft)^2 × 40 ft
= 3.14 × 1 × 40 ft^3
= 125.6 ft^3.
Each 40-foot section holds 125.6 cubic feet of water.
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