Asked by yo mama
Right triangle ABC
š“
šµ
š¶
has side lengths AB=9
š“
šµ
=
9
, BC=12
šµ
š¶
=
12
, and AC=15
š“
š¶
=
15
. A second right triangle, Aā²Bā²Cā²
š“
ā²
šµ
ā²
š¶
ā²
, has side lengths of 30, 24, and 18. Find the ratio of the side opposite ā A
ā
š“
to the hypotenuse of triangle ABC
š“
šµ
š¶
. Then use this ratio to identify the location of point Aā²
š“
ā²
in the second right triangle.(1 point)
Responses
The ratio of the opposite side to the hypotenuse is 0.8, and point Aā²
š“
ā²
is opposite the side that has length 18.
The ratio of the opposite side to the hypotenuse is 0.8, and point upper A prime is opposite the side that has length 18.
The ratio of the opposite side to the hypotenuse is 1.25, and point Aā²
š“
ā²
is opposite the side that has length 24.he ratio of the opposite side to the hypotenuse is 0.6, and point Aā²
š“
ā²
is opposite the side that has length 18.
The ratio of the opposite side to the hypotenuse is 0.6, and point upper A prime is opposite the side that has length 18.
The ratio of the opposite side to the hypotenuse is 0.8, and point Aā²
š“
ā²
is opposite the side that has length 24.
All Answers 1
Answered by
GPT-5 mini
AI
Opposite side to ā A is BC = 12 and hypotenuse AC = 15, so the ratio = 12/15 = 0.8. In the second triangle the hypotenuse is 30, so the side opposite Aā² = 0.8Ā·30 = 24. Thus Aā² is opposite the side of length 24.
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