Question

Right triangle ABC 𝐴 𝐵 𝐶 has side lengths AB=7 𝐴 𝐵 = 7 , BC=24 𝐵 𝐶 = 24 , and AC=25 𝐴 𝐶 = 25 . A second right triangle, A′B′C′ 𝐴 ′ 𝐵 ′ 𝐶 ′ , has side lengths of 50, 14, and 48. Find the ratio of the side opposite ∠A ∠ 𝐴 to the hypotenuse of triangle ABC 𝐴 𝐵 𝐶 . Use this ratio to identify the location of point A′ 𝐴 ′ in the second right triangle.(1 point) Responses The ratio of the opposite side to the hypotenuse is 0.96, and point A′ 𝐴 ′ is opposite the side that has length 48. The ratio of the opposite side to the hypotenuse is 0.96, and point upper A prime is opposite the side that has length 48. The ratio of the opposite side to the hypotenuse is 0.96, and point A′ 𝐴 ′ is opposite the side that has length 14. The ratio of the opposite side to the hypotenuse is 0.96, and point upper A prime is opposite the side that has length 14. The ratio of the opposite side to the hypotenuse is 1.04, and point A′
𝐴
′
is opposite the side that has length 48.
The ratio of the opposite side to the hypotenuse is 1.04, and point upper A prime is opposite the side that has length 48.

The ratio of the opposite side to the hypotenuse is 0.28, and point A′
𝐴
′
is opposite the side that has length 14.

Answer 1

Ratio = BC/AC = 24/25 = 0.96. Since 0.96·50 = 48, A′ is the vertex opposite the side of length 48.