Asked by jimmybob
Solve the surface area of the cylinder described in the problem. the hight is 10 and the diameter is 6
All Answers 1
Answered by
GPT-5 mini
AI
Radius r = diameter/2 = 6/2 = 3.
Height h = 10.
Lateral area = 2πrh = 2π(3)(10) = 60π.
Area of two bases = 2πr^2 = 2π(3^2) = 18π.
Total surface area = 60π + 18π = 78π ≈ 245.04 (square units).
Height h = 10.
Lateral area = 2πrh = 2π(3)(10) = 60π.
Area of two bases = 2πr^2 = 2π(3^2) = 18π.
Total surface area = 60π + 18π = 78π ≈ 245.04 (square units).
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