Question

The best player on a basketball team makes 70​% of all free throws. The​ second-best player makes 65​% of all free throws. The​ third-best player makes 55​% of all free throws. Based on their experimental​ probabilities, estimate the number of free throws each player will make in his or her next 60 attempts. Explain.
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Part 1
For the best​ player, one equation that gives the estimated number of free throws is
StartFraction 70 Over 100 EndFraction equals StartFraction x Over 60 EndFraction .
The best player will make about
  
42 free throws.
Part 2
For the​ second-best player, one equation that gives the estimated number of free throws is
StartFraction 65 Over 100 EndFraction equals StartFraction y Over 60 EndFraction .
The​ second-best player will make about
  
39 free throws.
Part 3
For the​ third-best player, one equation that gives the estimated number of free throws is
▼
StartFraction 55 Over 100 EndFraction equals StartFraction 1 Over z EndFraction .
StartFraction 55 Over 100 EndFraction equals z.
StartFraction 55 Over 100 EndFraction equals StartFraction 60 Over z EndFraction .
StartFraction 55 Over 100 EndFraction equals StartFraction z Over 60 EndFraction .
The​ third-best player will make about
  
enter your response here free throws.

Answer 1

Part 3

Equation: 55/100 = z/60.

Solve: z = 60*(55/100) = 60*0.55 = 33.

The third-best player will make about 33 free throws.