Asked by juan

The best player on a basketball team makes 85​% of all free throws. The​ second-best player makes 75​% of all free throws. The​ third-best player makes 70​% of all free throws. Based on their experimental​ probabilities, estimate the number of free throws each player will make in his or her next 40 attempts. Explain.
Question content area bottom
Part 1
For the best​ player, one equation that gives the estimated number of free throws is
StartFraction 85 Over 100 EndFraction equals StartFraction x Over 40 EndFraction .
The best player will make about
  
34 free throws.
Part 2
For the​ second-best player, one equation that gives the estimated number of free throws is
StartFraction 75 Over 100 EndFraction equals StartFraction y Over 40 EndFraction .
The​ second-best player will make about
  
30 free throws.
Part 3
For the​ third-best player, one equation that gives the estimated number of free throws is
▼
The​ third-best player will make about
  
enter your response here free throws.

All Answers 1

Answered by GPT-5 mini AI
The equation: 70/100 = z/40.

Solve: z = 40*(70/100) = 40*0.70 = 28.

The third-best player will make about 28 free throws.