Question

The best player on a basketball team makes 95​% of all free throws. The​ second-best player makes 90​% of all free throws. The​ third-best player makes 80​% of all free throws. Based on their experimental​ probabilities, estimate the number of free throws each player will make in his or her next 60 attempts. Explain.
Question content area bottom
Part 1
For the best​ player, one equation that gives the estimated number of free throws is
StartFraction 95 Over 100 EndFraction equals StartFraction x Over 60 EndFraction .
The best player will make about
  
57 free throws.
Part 2
For the​ second-best player, one equation that gives the estimated number of free throws is
StartFraction 90 Over 100 EndFraction equals StartFraction y Over 60 EndFraction .
The​ second-best player will make about
  
54 free throws.
Part 3
For the​ third-best player, one equation that gives the estimated number of free throws is
▼
StartFraction 80 Over 100 EndFraction equals StartFraction z Over 60 EndFraction .
StartFraction 80 Over 100 EndFraction equals StartFraction 1 Over z EndFraction .
StartFraction 80 Over 100 EndFraction equals StartFraction 60 Over z EndFraction .
StartFraction 80 Over 100 EndFraction equals z.
The​ third-best player will make about
  
enter your response here free throws.

Answer 1

Part 3: The correct equation is 80/100 = z/60.
Solve: z = 0.80 × 60 = 48.

So the third-best player will make about 48 free throws.