Question

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Part 1
The best player on a basketball team makes 95​% of all free throws. The​ second-best player makes 90​% of all free throws. The​ third-best player makes 80​% of all free throws. Based on their experimental​ probabilities, estimate the number of free throws each player will make in his or her next 60 attempts. Explain.
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Part 1
For the best​ player, one equation that gives the estimated number of free throws is
StartFraction 95 Over 100 EndFraction equals StartFraction x Over 60 EndFraction .
The best player will make about
  
57 free throws.
Part 2
For the​ second-best player, one equation that gives the estimated number of free throws is
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StartFraction 90 Over 100 EndFraction equals y.
StartFraction 90 Over 100 EndFraction equals StartFraction 1 Over y EndFraction .
StartFraction 90 Over 100 EndFraction equals StartFraction 60 Over y EndFraction .
StartFraction 90 Over 100 EndFraction equals StartFraction y Over 60 EndFraction .
The​ second-best player will make about
  
enter your response here free throws.

Answer 1

Choose StartFraction 90 Over 100 EndFraction = StartFraction y Over 60 EndFraction.
Solve: y = 0.90 × 60 = 54.
The second-best player will make about 54 free throws.